Five years ago man was seven times as hos son . Five years hence father will be three ti.es of s son.Find their present age
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Heya
Let the present age of the man be x and present.age of his son be y
According to the question,
x-5 = 7(y-5)
x-5 = 7y-35
x= 7y-30...(1)
x+5 = 3(y+5)
x+5 = 3y+15
x=3y+10...(2)
(1)-(2)
0 = 4y-40
40/4 = y
y= 10years
Substituting this in equation 1
x=7(10)-30
x=70-30
x=40years.
Age of the man is 40yrs and his son is 10yrs.
Hope it helps^_^
Let the present age of the man be x and present.age of his son be y
According to the question,
x-5 = 7(y-5)
x-5 = 7y-35
x= 7y-30...(1)
x+5 = 3(y+5)
x+5 = 3y+15
x=3y+10...(2)
(1)-(2)
0 = 4y-40
40/4 = y
y= 10years
Substituting this in equation 1
x=7(10)-30
x=70-30
x=40years.
Age of the man is 40yrs and his son is 10yrs.
Hope it helps^_^
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