Question

Five years ago man was seven times as hos son . Five years hence father will be three ti.es of s son.Find their present age

Answer 1

Heya

Let the present age of the man be x and present.age of his son be y

According to the question,

x-5 = 7(y-5)

x-5 = 7y-35

x= 7y-30...(1)

x+5 = 3(y+5)

x+5 = 3y+15

x=3y+10...(2)

(1)-(2)

0 = 4y-40

40/4 = y

y= 10years

Substituting this in equation 1

x=7(10)-30

x=70-30

x=40years.

Age of the man is 40yrs and his son is 10yrs.

Hope it helps^_^