five years ago man was seven times son's age.after five years he will be three times his son age. find their ages
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let the age of man = x
let the age of son = y
A.T.Q
five years ago,
(x-5) = 7(y-5)
x-5 = 7y - 35
x- 7y = -30---------------(1)
five years later,
(x+5) = 3(y+5)
x+5 = 3y + 15
x-3y = 10
x = 10+3y--------------(2)
Putting x value in equation (1) we get,
10 + 3y - 7y = -30
solve it for the value for y we get
y = 10
putting y value in equation 2 we get
x = 40
If it helps then plz mark it as brainlist
THANKS :)
let the age of son = y
A.T.Q
five years ago,
(x-5) = 7(y-5)
x-5 = 7y - 35
x- 7y = -30---------------(1)
five years later,
(x+5) = 3(y+5)
x+5 = 3y + 15
x-3y = 10
x = 10+3y--------------(2)
Putting x value in equation (1) we get,
10 + 3y - 7y = -30
solve it for the value for y we get
y = 10
putting y value in equation 2 we get
x = 40
If it helps then plz mark it as brainlist
THANKS :)
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