Question

five years ago monu was thrice as Sony ten years later monu will be twice as old as Sonu how old are Sony and monu?​

Answer 1

Given,

• five years ago,monu age is thrice as sony

• ten years later monu age will twice as old as sony

To Find:

present age of monu and sony

Solution:

Let the present age of monu = x years

Let the present age of sony = y years

Five years ago,

age of monu = x - 5

age of sony = y - 5

monu was thrice as old as sony:

$⟹x - 5 = 3(y - 5)$

$⟹x - 5 = 35 - 15$

$⟹x - 3y = - 15 + 5$

$⟹x - 3y = - 10 \: \: \: \: \: \: ........(1)$

ten years later,

age of monu = x + 10

age of sony = y + 10

monu will be twice as old as sony

$⟹x + 10 = 2(y + 10)$

$⟹x + 10 = 2y + 20$

$⟹x - 2y = 10 \: \: \: \: \: \: .......(2)$

$⟹x - 3y = - 10 \: \: \: \: \: .......(1)$

Subtracting equation (1) from equation (2)

we get,

$⟹$$\tt\underline{y = 20}$

plug this value in equation first we get,

$⟹x - 3 \times 20 = - 10$

$⟹x = 60 - 10$

$⟹$$\tt\underline{x = 50}$

Hence,

${\boxed{\tt{\red{age\:of\:sony\:is\:20}}}}$

${\boxed{\tt{\red{age\:of\: monu\:is\:50}}}}$