Question

Five years ago, Mr. Rashid was three times as old as his son was then. Five years from now, Mr. Rashid will be twice his son's age. Find their present ages

Answer 1

Answer:

Let us consider

Son’s age = X

Two years ago son’s age = X – 2

His Father’s age at that time = 3(X – 2)

Present age of Father = 3X – 6 + 2

The present age of Father = 3X – 4

Two years hence father’s age = 3X – 4 + 2

Two years hence father’s age = 3X – 2

Two years hence son’s age = X + 2

Given:

5 × (X + 2) = 2 × (3X – 2)

5X + 10 = 6X – 4

X = 14

Son’s present age X = 14 years.

Father’s present age = (3 × 14) – 4

Father’s present age = 38 years

Answer 2

Step-by-step explanation:

lets take the age of son = p

age of father be = 2p

hence there ages are = 5+2p..