Question

Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as
old as Sonu. How old are Nuri and Sonu?​

Answer 1

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Step-by-step explanation:Let the present age of Nuri  =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10                       ………..(1)

Ten years later,

Age of Nuri  =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10                           ………..(2)

X–3y=−10                        ………..(1)

Subtracting equation (1) from equation (2)  we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age  of Nuri =50 years and age of Sonu =20 years

Answer 2

before five years

sonu age = x -5

Nuri age= 3x-5

after 10 year

Nuri age = 2x+10

sonu age = x +10

ATQ

{x-5 }+{3x-5}= {2x+10}+{x+10}

4x=3x+20

x=20