Question

Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu? ( write some steps and type answer)​

Answer 1

Answer:

Let, Five years ago,

Sonu's age = x

nuri's age = 3x

After 10 Years,

Sonu's age = x + 5 + 10 => x + 15

Nuri's age = 3x + 5 + 10 = 3x + 15

According to the question,

3x + 15 = 2(x + 15)

3x + 15 = 2x + 30

3x - 2x = 30 - 15

x = 15

Answer 2

Step-by-step explanation:

$\bf{\underline{\underline\red{Given:-}}}$

• Five years ago, Nuri was thrice as old as Sonu

• Ten years later, Nuri will be twice as old as Sonu.

$\bf{\underline{\underline\blue{To\:Find:-}}}$

• The present ages of Nuri and Sonu.

$\bf{\underline{\underline\green{Solution:-}}}$

Let the age of Nuri be x

And age of Sonu be y

According to the 1st condition:-

Five years ago, Nuri was thrice as old as Sonu

Five years ago

Age of Nuri = x - 5

Age of Sonu = y - 5

Nuri will be thrice as old as Sonu

→ x - 5 = 3( y -5 )

→ x - 5 = 3y - 15

→ x - 3y = -15 + 5

$\rm \pink{→ x - 3y = -10.......(i)}$

According to 2nd condition:-

Ten years later, Nuri will be twice as old as Sonu.

Ten years later

Age of Nuri = x + 10

Age of Sonu = y + 10

Nuri will be twice as old as Sonu.

→ x + 10 = 2( y + 10 )

→ x + 10 = 2y + 20

→ x - 2y = 20 - 10

$\rm \orange{→ x - 2y = 10.......(ii)}$

Subtracting equation (i) from (ii)

→ x - 2y - ( x - 3y) = 10 - ( -10)

→ x - 2y - x +3y = 20

→ y = 20

Substituting y = 20 in equation (ii)

→ x - 2y = 10

→ x - 2(20) = 10

→ x - 40 = 10

→ x = 10 + 40

→ x = 50

$\boxed{ \rm \red{ Present \: age \: of \: Nuri \: = \: 50 \: years}}$

$\boxed{ \rm \purple{ Present \: age \: of \: Sonu \: = \: 20 \: years}}$