Question

Five years ago, Nuri was thrice as old as Sonu. Ten years later Nuri will be twice as old as Sonu. How old are Nuri and Sonu

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Answer 1

Answer:

So, the present age of Nuri will be- X = 50 years

and the present age of Sonu will be- Y = 20 years

Step-by-step explanation:

Let present age of Nuri- X years

Sonu- Y years

Five years ago;

Nuri's age- X -5

Sonu's age- Y -5

Given that Nuri was thrice old as Sonu

x-5 = 3 [y-5]

x-5 = 3y - 15

x- 3y = -10

Ten years later;

Nuri's age= x + 10 years

Sonu's age= y + 10 years

Given that Nuri will be twice old as Sonu

x + 10 = 2 [y + 10]

x + 10 = 2y + [10]

x + 10  = 2y + 20

x- 2y = 20 - 10

x - 2y = 10

Hence our equation is;

x - 3y = -10

x - 2y = 10

-y = -20

y = 20

putting y = 20 in [1]

x - 3y = -10

x - 3 [20] = -10

x- 60 = -10

x = -10 + 60

x = 50

So, the present age of Nuri will be- X = 50 years

and the present age of Sonu will be- Y = 20 years

Answer 2

Answer:

$\huge{\mathcal{\underline{\green{Answer}}}}$

Let the present age of Nuri =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10 ………..(1)

Ten years later,

Age of Nuri =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10 ………..(2)

X–3y=−10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3×20=−10

X=60–10

X=50

Hence age of Nuri =50 years and age of Sonu =20 years