Question

five years ago nuri was thrice as old as Sony. ten years ago, nuri will be twice as old as sonu. how old are nuri and sonu.​

Answer 1

Answer:

Step-by-step explanation:

let the present age of nuri be:x

and present age of sonu be :y

according to the question

x-5=3(y-5)

3y-x-10=0 (eqn 1)

also given in the question:

x+10=2(y+10)

2y -x +10=0 (eqn2)

subtract eqn 2 from eqn 1  we get :

y-20=0

hence y=20

subsitute value of y in eqn 1 we get

x=50

hence age of nuri:50 yrs

age of sonu:20 yrs

Answer 2

Step-by-step explanation:

Let age of Nuri = X

Let age of Sony = Y

First, five years ago (-5)

x - 5 = 3(y-5)

x - 5 = 3y - 15

x = 3y - 10

3y - x = 10  (i)

Now ten years ago,

x + 10 = 2(y + 10)

x + 10 = 2y + 20

x = 2y + 20 - 10

x = 2y + 10

2y - x = - 10 (ii)

Now solve for X and then using that find the age of Sonu.