Math, asked by aravindpramod007, 1 year ago

Five years ago Nuri was thrice old as Somu. Ten years later, Nuri
will be twice as old as Sonu. The present age, in years, of Nuri
and Sonu are respectively how much??

Answers

Answered by JunaidMirza
2

Answer:

Nuri = 50 yrs, Sonu = 20 yrs

Step-by-step explanation:

Present age of:

Nuri = N

Somu = S

5 years ago

(N - 5) = 3(S - 5)

N - 5 = 3S - 15

N = 3S - 10 ....(1)

10 years later

(N + 10) = 2(S + 10)

N + 10 = 2S + 20

N = 2S + 10 .....(2)

From equation (1) & (2)

3S - 10 = 2S + 10

S = 20 yrs

If S = 20 then from equation (1)

N = 3S - 10

= (3 × 20) - 10

= 60 - 10

= 50 yrs

Answered by Anonymous
30

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Let us assume, the present age of Nuri is x.

And the present age of Sonu is y.

According to the given condition, we can write as;

x – 5 = 3(y – 5)

x – 3y = -10…………………………………..(1)

Now,

x + 10 = 2(y +10)

x – 2y = 10…………………………………….(2)

Subtract eq. 1 from 2, to get,

y = 20 ………………………………………….(3)

Substituting the value of y in eq.1, we get,

x – 3(20) = -10

x – 60 = -10

x = 50

Therefore ,

Age of Nuri is 50 years

Age of Nuri is 50 yearsAge of Sonu is 20

Hope it's Helpful.....:)

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