Math, asked by shreyyasscr7, 7 months ago

Five years ago Pooja was twice Sachi’s age. Five years hence, their age will be in the ratio 4:3. Find their present age pls.

Answers

Answered by antarahabra02
0

Step-by-step explanation:

Let present age of Sanchi is X and Pooja is Y

Then five tears ago (Y-5) = 2*(X-5) or Y=2X-5

After 5 years (Y+5)/(X+5)= 4/3 or 3Y+15 = 4X+20

3(2X-5)+15 = 4X+20 or 6X-15+15 =4X+20

2X= 20 or X=10 (Present age of Saanchi)

Y=2x-5 = 15 (Present age of Pooja) (Ans)

Answered by Shiva1206
1

Step-by-step explanation:

Let the Sanchi 5years ago=x years

Let the Sanchi 5years ago=x yearsThen the age of puja 5years ago=2x yrs

Now present age of Sanchi=(x+5) years

Present age of Pooja= (2x+5) years

Five years ago:

Sanchi's age = (x+10) years

Pooja age = (2x+10) years

Now

3(2x+10)=4(x+10)

x=5

So, present age of Sanchi = 5+5= 10yrs.

Present of pooja age= 2(5)+5 = 10+5

=) 15 years

Hope it helps u bye

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