Math, asked by narebdrmodi7692, 1 year ago

five years ago pooja was twice sachin's age. five years hence,their age will be in the ratio 4:3 find their present ages

Answers

Answered by devanayan2005
0

Answer: Sachin's age = 1 years

              Pooja's age = 2 years

Step-by-step explanation:

let sachin's present age be x years

let pooja's present age be 2x years

five years ago:

sachin's age=( x-5 ) years

poojas age= (2x-5) years

five years hence:

sachin's age= 3(x-5) years

pooja's age= 4(2x-5) years

A.T.Q

4(2x-5) = 3(x-5)

→8x - 20 = 3x - 15

→8x - 3x = -15 + 20

→5x = 5

→x = 5/5

→x = 1

∴Sachin's present age is 1 years

and Pooja's present age is 2 years.

Thank you:)

Hope this helps you:)

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