Question

Five years ago, pradip was three times as old as sudip. 10 years later, Pradip would be twice old as sudip. How old are they now?​

Answer 1

Answer:

Age of Pradip is 20 years age of Sudip is 50 years

Answer 2

✬ Pradip's Age = 20 Years ✬

✬ Sudip's Age = 50 Years ✬

Step-by-step explanation:

Given:

• 5 years ago age of Pradip was 3 times of Sudip.
• After 10 years age of Pradip will be twice the age of Sudip.

To Find:

• Present ages of both ?

Solution: Let the present ages Pradip and Sudip be x and y respectively.

[ Five years ago their ages were ]

• Pradip's age = (x – 5) years

• Sudip's age = (y – 5) years

A/q

➛ Pradip's age was 3 times of Sudip's age

➛ 3(x – 5) = (y – 5)

➛ 3x – 15 + 5 = y

➛ 3x – 10 = yㅤㅤㅤㅤㅤ(eqⁿ 1)

[ After 10 years their ages will be ]

• Pradip's age = (x + 10) years

• Sudip's age = (y + 10) years

A/q

➟ Pradip will be twice the age of Sudip.

➟ 2(x + 10) = (y + 10)

➟ 2x + 20 – 10 = y

➟ 2x + 10 = 3x – 10

➟ 10 + 10 = 3x – 2x

➟ 20 = x

So the present age of Pradip is 20 years & present age of Sudip is

➮ y = 3x – 10

➮ y = 3 × 20 – 10

➮ y = 50 years.