five years ago Raju was twice as old as peter 5 years later his age will be 5 more than Peter age find their present ages
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Answers
Answer:
Present age of Raju is 15 years and the present age of Peter is 10 years.
Step-by-step explanation:
Given :-
- 5 years ago, Raju was twice as old as Peter.
- 5 years later, his age will be 5 more than Peter's age.
To find :-
- Their present ages.
Solution :-
Let the present age of Raju be x years and the present age of Peter be y years.
5 years ago,
- Age of Raju = (x-5) years
- Age of Peter = (y-5) years
According to the question,
(x-5) = 2(y-5)
→ x-5 = 2y-10
→ x = 2y-10+5
→ x = 2y -5.................(i)
After 5 years,
- Age of Raju = (x+5) years
- Age of Peter = (y+5) years
According to the question,
x+5 = (y+5)+5
→ x+5 = y +10
- Put x = 2y-5 from eq (i).
→ 2y-5+5 = y + 10
→ 2y = y +10
→ 2y-y = 10
→ y = 10
- Present age of Peter = 10 years.
Now put y = 10 in eq(i) for getting the value of x.
x = 2y-5
→ x = 2×10 - 5
→ x = 20-5
→ x = 15
- Present age of Raju = 15 years.
Step-by-step explanation:
Let the age of Peter be x years and age of Raju be y years.
________________....
Now, According to given question :
★ 5 years ago :-
- Age of Raju = y - 5
- Age of Peter = x - 5
y - 5 = 2(x - 5)
y - 5 = 2x - 10
y = 2x - 10 + 5 ..........(equation 1)
........----------------------------------........
★ After 5 years :-
- Age of Raju = y + 5
- Age of Peter = x + 5
(y + 5) = (x + 5) + 5
y + 5 = x + 10
x - y = 10 - 5
x - y = 5
x = y + 5 .......... (equation 2)
____________________
Now, put the value of x = y + 5 in equation (1) :
y = 2x - 10 + 5
y = 2(y + 5) + 5
y = 2y + 10 + 5
2y - y = 15
y = 15 years
___________________
Putting the value of y = 15 in equation (1) :
y = 2x - 10 + 5
15 = 2x - 5
2x - 5 = 15
2x = 15 + 5
2x = 20
x = 10 years
Therefore,
- Present age of Raju = 15 years.
- Present age of Peter = 10 years.