Math, asked by srinivas4365, 5 months ago

Five years ago, Ramu was thrice as old as Somu and ten years later, Ramu will be twice
as old as Somu. Then the present ages of Ramu and Somu respectively are
(1) 35, 20
(2)20, 35
(3)20,50
(4)50,20​

Answers

Answered by nikunjc971
1

Step-by-step explanation:

Five years ago

Age of Ramu= x – 5 years

Age of Somu = y – 5 years

Ramu was thrice as old as Sonu

X- 5 = 3(y – 5)

X – 5 = 35 – 15

X – 3y = -15 + 5

X – 3 y = - 10 ………..(1)

Ten years later,

Age of Ramu = x + 10

Age of Somu = y + 10

Ramu will be twice as old as Sonu.

X+ 10 = 2(y+10)

X + 10 = 2y + 20

X – 2y = 10 ………..(2)

X – 3 y = - 10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3×20=−10

X = 60 – 10

X=50

Hence age of Ramu=50 years and age of Somu=20 years

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