Math, asked by sujanareddy2004, 8 months ago

Five years ago, Sagar was twice as old as Srinu. Ten years later, Sagar’s age will be ten years more than Srinu’s age. Find their present ages

Answers

Answered by mohdreha
2

Tiru = 15 Years

Sagar = 25 Years

Sagar was 10 Years old when Tiru Born

Five years ago, Sagar was twice as old as Tiru. Ten years later Sagar's age will be ten years more than Tiru's age. Find their present ages. What was the age of Sagar when Tiru was born. Solve it graphically.

Let say present age of Sagar = S Years

Let Say present age of Tiru = T   Years

Five year Ago Sagar Age = S - 5

Five year Ago Tiru Age = T - 5

Five years ago, Sagar was twice as old as Tiru.

S -5 = 2(T-5)

=> S - 5 = 2T - 10

=> 2T = S + 5

Ten year Later Sagar Age = S + 10

Ten year Later Tiru Age = T + 10

S + 10 = T + 10 + 10

=> S = T + 10

2T = S + 5

=> 2T = T + 10 + 5

=> T = 15

S = 15 + 10 = 25

Tiru Present age = 15 Years

Sagar Present age = 25 Years

Tiru was born 15 years ago so sgar age 15 years ago = 25 - 15 = 10 Years

Sagar was 10 Years old when Tiru Born

Answered by reddysruthi028
2

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