Question

five years ago seema was twice as old as Rita. five years later seema age will be 5 more than Rita age. find their present ages

Answer 1

Let Age Of Rita 5 years ago=x years

Then Age Of seema 5 years ago=2x years.

After 5 years means Present,

Age Of Rita Now=x+5 years

Age of Seema Now=2x+5 years

Five Years Later.

Age of Rita=x+5+5=x+10 years

Age of Seema is 5 more than Rita age.

Seema Age =2x+5+5=2x+10 years

Age of Seema is 5 more than Rita age.

MEANS Seema Age=(x+10)+5=x+15 years

Seema Both Age is Same

2x+10=x+15

2x-x=15-10

x=5 years

Rita Present Age=x+5=5+5 =10 years

Seema Present =2x+5=2×5+5=15 years

Check

5 years Ago Seema was TWICE as Rita

Rita was=X=5

seema was=2x=2×5=10

5 years Later

Seema is 2x+10=2×5+10=20 years

She is also 5 more than age of rita 5years later.

x+10+5

=5+5+10=20 years.

Hence Proved.

$\boxed{\mathbf{Rita=10\: years}}$

$\boxed{\mathbf{Seema=15\: years}}$