Math, asked by thakurhimanshu3993, 9 months ago

Five years ago shikha was thrice as old as honey . 10 years later shikha will be twice as old as honey. how old they are now.​

Answers

Answered by Legend42
9

Answer:

Let the present ages of Shikha and Honey be "x" and "y" respectively.

Shikha's age 5 years before is  "x - 5"

Honey's age 5 years before is "y - 5"

x - 5 = 3(y - 5)

x - 5 = 3y -15

x - 3y  = -10            ------------> (1)

Also,

Their ages 10 years later is "x +10" and "y+10" respectively.

x + 10 = 2(y + 10)

x +10 = 2y + 20

x - 2y = 10                     -----------------------> (2)

Subtracting equation (2) from(1) , 

x - 3y = -10

x - 2y = 10

-------------------------

-y = -20

y = 20

x - 2y = 10

x - 40 = 10

x = 40 + 10 = 50

Present age of Shikha = x  = 50 years

Present age of Honey = y = 20 years

Plzzzzz mark me as branliest

Similar questions