Question

Five years ago sunitha 's mother was 7 times as old as sunitha five years hence she will be 3 times as old as sunitha. find their present ages. please give me answer . tomorrow is my exam

Answer 1

⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟

➫ Let daughter's & mother's present ages be x and y respectively.

➧ 5 years ago mother's age was 7 times her daughter's age:-

So,mother's will be
➾ y - 5 = 7(x - 5) 

➧ 5 years from now the mother's age will be:-
➾ y + 5 = 3(x + 5)

➤ By solving both the equations we get:-

➾ x = 10
　 y = 40

▶So the present ages of mother & her daughter are 40 & 10 years respectively.

_________
Thanks...✊

Answer 2

i know i know see

let the age of sunita be x

and her mother be y

five years ago sunitas mother was 7time her age

so,

7(x-5)=y-5
7x-35=y-5
7x-y=30(equation 1)

after 5 years she will be 3 times as old ans

sunita so
3(x+5)=y+5
3x+15=y+5
3x-y=–10(equation 2)


from eq^n (1) and (2)

hey buddy plzz mark as brainliest and see photo after completing this

mother age 40
and daughter 10