Question

Five years ago sunitha 's mother was 7 times as old as sunitha five years hence she will be 3 times as old as sunitha. find their present ages. please give me answer . tomorrow is my exam(linear equations in one variable)

Answer 1

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Let the age of father be x years.

Let the age of his son be y years.

 

10 years ago-

(x-10) = 12(y-10)

x-10 = 12y-120

(i) x-12y = -110

10 years after-

(x+10) = 2(y+10)

x+10 = 2y+20

(ii) x-2y = 10

Equations-

(i) x-12y = -110

(ii) x-2y = 10

Using substitution method-

x-12y = -110

x = 12y-110

Putting the value of x in the second equation-

x-2y = 10

12y-110-2y = 10

10y = 120

y = 12

Now, x-12y = -110

x-12(12) = -110

x-144 = -110

x = -110+144

x = 34

Present age of father = x = 34 years

Present age of son = y = 12 years

Answer 2

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