Math, asked by Anonymous, 10 months ago

Five years ago, the age of a father was twice the age of his son. The sum of their present ages is 70 years. Find their present ages.

Answers

Answered by thanushreereddy15
1

Step-by-step explanation:

Father 45 and Son 25

% years ago they had a combined age of 70. subtract 5 years per person. 60 years total between the two. Father was twice the age of the son. 2x + x = 3x/60; x=20 2x20 = 40 age of father x = 20 son. These were their ages 5 years ago. Add 5 years per individual.

40 plus 5 = 45 Age of Father

20 plus 5 =25 Age of Son

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