Question

Five years ago the age of father was twice as old as the age of daughter. The sum of present ages of the father and
daughter is 55 years then find their present ages​

Answer 1

Step-by-step explanation:

Father 45 and Son 25

% years ago they had a combined age of 70. subtract 5 years per person. 60 years total between the two. Father was twice the age of the son. 2x + x = 3x/60; x=20 2x20 = 40 age of father x = 20 son. These were their ages 5 years ago. Add 5 years per individual.

40 plus 5 = 45 Age of Father

20 plus 5 =25 Age of Son

Answer 2

Given :

• Five years ago the age of father was twice as old as the age of daughter.
• The sum of present ages of the father and
• daughter is 55 years.

To find :

• Their present ages =?

Step-by-step explanation :

Let, the present age of daughter's be, x.

Then, the present age of father's be, 2x.

It is Given that,

The sum of present ages of the father and

daughter is 55 years.

According to the question,

2x + x = 55 - (5 + 5)

3x = 55 - 10

3x = 45

x = 45/3

x = 15.

Therefore, We got the value of, x = 15.

Hence,

The present age of daughter's , x = 15 years

Then, the present age of father's, 2x = 2 × 15 = 30 years.