Question

five years ago, the age of the father is obtained by twice the sum of the ages of his three children. 5 years later, the age of the father was 8 less than the sum of the ages of his three children. Find the Present age of the father.
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Answer 1

Answer:

$let \: father \: age \: be \: x \\ \\let \: the \:sum \: of \: age \: of \: children \: \\ be \: y \\ \\ x - 5 = 2(y ) \\ \\ x - 2y = 5 \: \: \: \: - (i)\\ \\ x + 5 = (y) - 8 \\ \\ x - y = - 13\: \: \: - (ii) \\ \\ subtract \: (i)from(ii) \\ \\ we \: get \: y = - 18 \\ \\ put \: y = - 18n \:( i) \\ \\ age \: of \: father \: is \: - 31 \\ \\ mark \: it \: as \: brainiest \: and \: follow \: me$