Question

five years ago the avarege of A and B was 15 years avarege age of A, B, and C today is 20 years how old will C after 10 years ​

Answer 1

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$\huge\red\bigstar$ $\red{QUESTION:}$

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five years ago the avarege of A and B was 15 years avarege age of A, B, and C today is 20 years how old will C after 10 years .

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$\huge\green\bigstar$ $\red{ANSWER:}$

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•present age of A & B are a & b.

5 years before their age = $\pink{a-5}$ & $\pink{b-5}$ .

• so average age was 15.

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$So, \\ \frac{(a - 5) + (b - 5)}{2} = 15 \\ .°. \: a + b \: = 30 + 10 \\ .°. \: \red{a + b \: = 40 \: ..........(1)}$

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NOW, average age of a, b & c is 20.

$.°. \: \frac{a + b + c}{3} = 20 \\ .°.\green{a + b + c = 60 \: ........(2)}$

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From, equation $\red{1}$ & $\green{2}$

(a+b+c) - (a+b)=60-40

$\implies$ $\cancel{(a+b}+c)$ - $\cancel{(a+b})$ =20

.°. $\implies$ $\pink{c =20}$

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$\huge\red\bigstar$ $\purple{HENCE}$

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$\implies$ .°. Age of c after 10 year age is C =$\pink{(20+10)}$=$\green{30year.}$

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Answer 2

Step-by-step explanation:

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fuc you.