Question

Five years ago, the father was seven times as old as his
son. Five years hence, father's age will be three times the
age of his son. Find their present ages.​

Answer 1

Step-by-step explanation:

x-5=7(y-5)

x=3y

subtitute equation 2 in 1

3y-5=7y-35

10y=40

y=4

substitute y=4 in equation 2

x=3*4

x=12

x is father age y is son age

Answer 2

Answer:

mark it as a brainliest answer

Step-by-step explanation:

7x-5=3x+5

7x-3x=5+5

2x=10

x=10/2

x=5

3x=3×5

=15