Math, asked by guptaanindita48, 1 month ago

Five years ago, the ratio of A's age and B's
age was 5:6. The ratio of their ages will be
7:8, after five years. What is the ratio of the A's
present age and the B's present age ?​

Answers

Answered by Anonymous
17

Answer:

The ratio of age of A and B = 6 : 7

Step-by-step explanation:

Given:

  • Five years ago, the ratio of A's age and B's age was 5:6.
  • The ratio of their ages will be 7:8, after five years.

To find:

  • What is the ratio of the A's present age and the B's present age ?

Solution:

Present age be:

  • A : B = x : y

5 years ago,

  • A : B = 5 : 6
  • (x - 5) : (y - 5) = 5 : 6

Cross multiplication.

  • 6(x - 5) = 5(y - 5)
  • 6x - 30 = 5y - 25
  • 6x = 5y - 25 + 30
  • 6x = 5y + 5
  • x = (5y + 5)/6

5 years after,

  • A : B = 7 : 8
  • (x + 5) : (y + 5) = 7 : 8

Cross multiplication.

  • 8(x + 5) = 7(y + 5)
  • 8x + 40 = 7y + 35
  • 8x = 7y + 35 - 40
  • 8x = 7y - 5

Substituting x.

  • 8(5y + 5)/6 = 7y - 5

Cross multiplication.

  • 8(5y + 5) = 6(7y - 5)
  • 40y + 40 = 42y - 30
  • 40y - 42y = - 30 - 40
  • -2y = - 70
  • y = 35

Finding x:

  • x = (5y + 5)/6

Putting y.

  • x = (5 × 35 + 5)/6
  • x = (175 + 5)/6
  • x = 180/6 = 30

Hence,

  • A : B = x : y
  • A : B = 30 : 35
  • A : B = 6 : 7

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