Question

Five years ago, the total of the ages of a father and his son was 40 years. The ratio of their present ages is 4 : 1. What is the present age of the father ?

Answer 1

given,
5years ago
x+y=40
now ,
x +y = 4:1
4x , 1x
4x+1x= 40+5
5x= 45
x =45/5
x= 9
4x=36

NOW , THE SON IS 9 YEARS OLD AND THE FATHER IS 36 YEARS OLD

Answer 2

Answer:

40 years

Step-by-step explanation:

The ratio of father and his son present ages is 4 : 1.

Let the ratio be x

Father's present age = 4x

Son's age = x

Father'age 5 years ago = 4x-5

Son's age 5 years ago = x-5

Now we are given that Five years ago, the total of the ages of a father and his son was 40 years.

$4x-5+x-5=40$

$5x-10=40$

$5x=50$

$x=10$

Son's present age = 10

Father's present age = 4x=4*10=40

Hence the present age of the father is 40 years .