Question

Five years back my age was three times the age of my son.after 10 years,my age will be double that of my son.what is my present age?

Answer 1

Answer:

Step-by-step explanation:

Let your age and your son's age be x and y respectively (before 5 years)

Thus,

x=3y

=x - 3y = 0 ------(1)

After 10 ,

X+10 = 2(y +10 )

=x- 26 = 10 -------(2)

Now,

By subtracting,

We get

y=10. (Answer)

So,

x-3y =0

X=3*10

X=30.(answer)

Answer 2

Answer:

LET US PRESENT AGES OF THE FATHER AND SON BE x and y

Step-by-step explanation

GIVEN:

x - 5= 3(y-5)

by solving we get,

x - 3y = -10 (a) and

x - 10 =4(y-10)

x - 4y =-30(b)

by (a)-(b)  so we get y =20

substituting y = 20 in (a)

so we get x = 50

so father age is 50 years and son age is 20years