Question

Five years hence, a man's age will be three times the age of this son
Five years ago, the man was seven times as old as his son. Find their
present age​

Answer 1

Answer:

Let

The present age of man=x

The present age of son=y

A.to.q

1 case: (x+5) = 3(y+5)

x+5=3y+15

x-3y=15-5

x-3y=10_____(1)

2 case: (x-5)= 7(y-5)

x-5=7y-35

x-7y=-35+5

x-7y=-30_____(2)

from equation (1)&(2)

x-3y=10______(1)

x-7y=-30______(2)

__________

0-10y=-20

10y=20

y=20/10

[y=2]

putting the value of y in equation (1)

x-3(2)=10

x-6=10

[x=16]

The present age of man=16

The present age of son=2

Answer 2

Answer:

Step-by-step explanation:

Let seven years, age of Swati was x years and age of Varun was 5x² years

Present age of Swati = ( x + 7 ) years

Present age of Varun = ( 5x² + 7 ) years

Given, after 3 years swati's age will be 2 / 5 of Varun's age.

Age of Swati after 3 years = ( x + 7 + 3 ) years = ( x + 10 ) years

Age of Varun after 3 years = ( 5x² + 7 + 3 ) years = ( 5x² + 10 ) years

Given, age of Swati after 3 years = age of varun after 3 years

( x + 10 ) = 2 / 5 × ( 5x² + 10 )

( x + 10 ) = 2( x² + 2 )

x + 10 = 2x² + 4

2x² - x + 4 - 10 = 0

2x² - x - 6 = 0

2x² - 4x + 3x - 6 = 0

2x( x - 2 ) + 3( x - 2 ) = 0

x = 2 [ Age can't be negative ]

Therefore,

present age of Swati = ( 2 + 7 ) = 9 years

present age of Varun = 5(2)²+7=27 years

Read more on Brainly.in - https://brainly.in/question/4061764#readmore