Question

five years hence a mother age will be there time that of her daughters and 5 year ago the mother was 7 times as old as the daughter was find the present age​

Answer 1

Answer:

mothers age 40

daughter's age 10

Step-by-step explanation:

• let x be mother's age and y be daughter's age at present
• then after five years

mother's age = x + 5

daughter's age = y + 5

therefore ,

( x + 5 ) = 3( y + 5 ) (1)

• and five years ago

mother's age = x -5

daughter's age = y -5

therefore,

( x - 5 ) = 7( y - 5 ) (2)

• now solve equation 1 and 2 simultaneously
• the value of x and y will be answer