Question

Five years hence , father's age will be three times the age of his son. Five years ago , father was seven times as old as his son . Find their present ages.

Answer 1

Answer:

Step-by-step explanation:

Given :-

• Five years hence, a man's age will be three times the age of his son.
• Five years ago, the man was seven times as old as his son.

To Find  :-

• Their Present ages.

Solution :-

Let the present age of the man be x years.

And His son's  be y years.  

1st Equation :-

After 5 years man’s age = x + 5  

After 5 years ago son’s age = y + 5  

According to the question ,

⇒ x + 5 = 3(y + 5) x - 3y = 10 ……………(i)  

2nd Equation :-

5 years ago man’s age = x - 5  

5 years ago son’s age = y - 5  

As per the question

⇒ x - 5 = 7(y - 5)

⇒ x - 7y = -30 …….(ii)

Subtracting (ii) from (i), we have  

⇒ 4y = 40  

⇒ y = 10  

Putting y value in Eq (i)

⇒ x - 3y = 10

⇒ x - 3 × 10 = 10  

⇒ x = 10 + 30

⇒ x = 40

Hence, man’s present age is 40 years and son’s present age is 10 years.

Answer 2

Answer:

• Present age of father = 40 years
• Present age of his son = 10 years.

Step-by-step explanation:

Let , the father's present age be "f" and his son's present age be "s".

Question :-

Five years hence , father's age will be three times the age of his son. Five years ago , father was seven times as old as his son . Find their present ages.

( SOLUTION AND STEPS ARE IN ATTACHMENT )