Math, asked by akashdeep38939, 1 year ago

Five years hence the age of Ali will be three times of his son . Five years ago Ali's age was seven times of his son find their present ages​

Answers

Answered by Mahimasharan971
3

Hey mate

Here is your answer

Let present age of Ali = x year

And present Age of his son is = y year.

Five years hence,

Age of Ali will = x + 5 year

Age of his son will = y + 5year

Given that the age of Ali will be 3 times that of his son

x + 5 =3(y+5)

Add 5 both side we get

x = 3y + 15 - 5

x = 3y + 10 … (1)

Five years ago,

Age of Ali will = x - 5 year

Age of his son will = y - 5year

Ali’s age was seven times that of his son

x – 5 = 7(y -5)

Plug the value of x from equation (1) we get

3y + 10 – 5 = 7 y – 35

3y + 5 = 7y – 35

3y – 7 y = - 35 – 5

-4y = - 40

y = - 40 / - 4

y = 10 year

Plug the value of y in equation first we get

x = 3* 10 + 10

x = 40 years

Answer is

Present age of Ali = 40 years

Present age of his son = 10 years

Answered by sunnysinghdollysingh
2

Answer:

ali 40, son 10

Step-by-step explanation:

given ali+5=3(son+5)

and  ali-5=7(son-5)

equating these equations cancels ali and we can find son age as 10 years

substituting son age in above 2 equations gives ali age as 40 years

please mark as brainlest bro

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