Math, asked by sharmamridul78, 9 months ago

Five years hence, the age of father will be 10 years more than twice the age of the son. Taking the present age of father and son as x and y years respectively, then the linear equation representing the above situation is

a. x - 2y - 25 = 0
b. x - 2y - 20 = 0
c. x - 2y - 15 = 0
d. 2x - y + 15 = 0

Answers

Answered by Anonymous
4

Given :

  • Five years hence, the age of father will be 10 years more than twice the age of the son.
  • The present age of father and son as x and y years respectively.

To find :

  • Linear equation representing the above situation.

Solution :

  • Present age of father = x years
  • Present age of son = y years

After 5 years,

  • Age of father = (x+5) years
  • Age of son = (y+5) years

According to the question :-

  • Five years hence, the age of father will be 10 years more than twice the age of the son.

\implies\sf{x+5=2(y+5)+10}

\implies\sf{x+5=2y+10+10}

\implies\sf{x+5=2y+20}

\implies\sf{x-2y+5-20=0}

\implies\sf{x-2y-15=0}

Therefore, the required linear equation representing the above situation is x-2y-15 = 0.

Hence,

Correct answer is option (c).

Answered by silentlover45
0

  \huge \mathfrak{Answer:-}

\implies x - 2y - 15 = 0

\large\underline\mathrm{Given:-}

  • Five years hence, the age of father will be 10 years more than twice the age of the son.
  • The present age of father and son as x and y years respectively.

\large\underline\mathrm{Solution}

  • present age of father = x year's
  • present age of son = y year's

\large\underline\mathrm{After \: 5 \: year's}

  • Age of father = x + 5 year's
  • Age of son = y + 5 year's

\large\underline\mathrm{According \: to \: the \: questions}

  • Five years hence, the age of father will be 10 years more than twice the age of the son.

\implies x + 5 = 2(y + 5) + 10 = 0

\implies x + 5 = 2y + 10 + 10 = 0

\implies x + 5 = 2y + 20 = 0

\implies x - 2y + 5 - 20 = 0

\implies x - 2y - 15 = 0

\large\underline\mathrm{hence,}

\large\underline\mathrm{the \: required  \: linear \: equations \: respecting \: the \: above \: situation \: is \: x \: - \: 2y \: - \: 15 \: = \: 0.</p><p>}

\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}

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