Five years hence, the age of father will be 10 years more than twice the age of the son. Taking the present age of father and son as x and y years respectively, then the linear equation representing the above situation is
a. x - 2y - 25 = 0
b. x - 2y - 20 = 0
c. x - 2y - 15 = 0
d. 2x - y + 15 = 0
Answers
Answered by
4
Given :
- Five years hence, the age of father will be 10 years more than twice the age of the son.
- The present age of father and son as x and y years respectively.
To find :
- Linear equation representing the above situation.
Solution :
- Present age of father = x years
- Present age of son = y years
After 5 years,
- Age of father = (x+5) years
- Age of son = (y+5) years
According to the question :-
- Five years hence, the age of father will be 10 years more than twice the age of the son.
Therefore, the required linear equation representing the above situation is x-2y-15 = 0.
Hence,
Correct answer is option (c).
Answered by
0
x - 2y - 15 = 0
- Five years hence, the age of father will be 10 years more than twice the age of the son.
- The present age of father and son as x and y years respectively.
- present age of father = x year's
- present age of son = y year's
- Age of father = x + 5 year's
- Age of son = y + 5 year's
- Five years hence, the age of father will be 10 years more than twice the age of the son.
x + 5 = 2(y + 5) + 10 = 0
x + 5 = 2y + 10 + 10 = 0
x + 5 = 2y + 20 = 0
x - 2y + 5 - 20 = 0
x - 2y - 15 = 0
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