Math, asked by lakshyarajput830786, 10 months ago

five years hence,the age of jacob will be three times of his son.five years ago, jacob age was seven times of his son. what was their present ages?​

Answers

Answered by vedantlabana07
0

Step-by-step explanation:

jacob age was 40 years and his son age is 10 year; at present time

Answered by BrainlyGloriousGrl
7

Step-by-step explanation:

HLW MATE.....HERE IS YOUR CORRECT QUESTION :

✓Five years hence, the age of jacob will be three times that of his son. Five years ago , jacob's age was seven times that of his son. what are their present ages?

✓YOUR CORRECT ANSWER :

Let the age of jacob be 'x' and his son be 'y'.

ATQ,

x+5=(y+5)

x-5=(y-5)

x+5=3y+15

x-3y=15-5

x-3y=10 -----------------(1)

x=10+3y

x-5=7y-35

x-7y=-35+5

x-7y=-30 ----------------(2)

SUBSTITUTE, x=10+3y in eq (2)

10+3y-7y=-30

-4y=-30-10

y=-40/-4

y=10

x=10+3(10)

x=10+30

x=40

✓THEREFORE,

THE PRESENT AGE OF JACOB IS 40 AND HIS SON IS 10

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