Math, asked by parthrisa2484, 11 months ago

Five years hence the age of jacob will be three times that of his son.Five years ago,jacob's age was seven times that of his son,what are their present age

Answers

Answered by muskan1010
1

Heya!!

Let the age of son five years ago be x

Then, Jacob's age five years ago be 7x

Now, son's present age be (x + 5)

Also, Jacob's present age be (7x + 5)

After five years son's age will be (x + 5 + 5)

= (x + 10)

Jacob's age after five years will be (7x + 5 + 5)

= (7x + 10)

According to the question

=> (7x + 10) = 3(x + 10)

=>7x + 10 = 3x + 30

=> 4x = 20

=> x = 5

Son's age = (x + 5) = (5 + 5) = 10

Jacob's age = (7x + 5) = (35 + 5) = 40

Hence, son's present age is 10 years and Jacob's present age 40 years.

#Hope it helps

#MarkasBrainliest

Answered by Anonymous
0

Answer:

Please refer the attachment dear

Attachments:
Similar questions