Question

five years hence the age of Jacob will be three times that of his son. five years ago, Jacob's age was seven times that of his son. what are their present ages? ??????...
Please ans me fast........​

Answer 1

Step-by-step explanation:

Let Jacob's son's age = x years

Let Jacob's age = y years

According to question

Five years hence

I.e. y + 5 = 3(x + 5) ...... (i)

Five years ago

I.e. y - 5 = 7(x - 5) ...... (ii)

Solving (i) and (ii)

x = 10 and y = 40

Hope it helps.

Answer 2

Answer

Step-by-step explanation:

10x+y=105 ------- 1

15x +y=115 --------2

on subtracting eq 1&2

10x+y=105

15x +y=115

=) 5x =10

x=2---------3

put value of x in eq 1

20+y=105

y=105-20

y=85---------4

same with y

x + 10y=105. on subtract

x+15y=155

5y=50

y=10

put value of xin eq above

x+10y=105

x=105-100

x=5