Question

Five years hence, the age of Jacob will be three times that of his son. Five years
ago, Jacob's age was seven times that of his son. What are their present ages?​

Answer 1

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Answer 2

Answer:

Let the present age of Jacob be x yrs

the present age of Jacob's son be y yrs .

Five yrs hence,

Age of Jacob =( x + 5) yrs

Age of Jacob's son = ( y+5) yrs

A/q

x + 5 = 3 ( y + 5 )

=> x + 5 = 3y + 15

=> x = 3y + 15 - 5

=> x = 3y + 10 ........................(1)

Five yrs ago,

Age of Jacob = ( x - 5 ) yrs

Age of Jacob's son = (y-5) yrs

A/q

x - 5 = 7( y - 5 )

=> x - 5 = 7y - 35

=> x = 7y - 35 + 5

=> x = 7y - 30..........................(2)

From ....... (1) and (2)

=> 3y + 10 = 7y - 30

=> 10 + 30 = 7y - 3y

=> 40 = 4y

=> 4y = 40

=> y = 40/4 = 10 yrs

And,

from .......(1)

x = 3y + 10

= 3 × 10 + 10

= 40 yrs..

Hence , the present age of Jacob is 40 yrs

the present age of Jacob's son is 10 yrs .

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