Question

five years hence the age of Jacob will be three times that of his son. Five years ago Jacob's age was seven times that of his son. what are their present ages​

Answer 1

ANSWER

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)x=5×10−10x=40Therefore Present age of Jacob is 40 years and his son is 10 years

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Answer 2

Answer:

Please refer the attachment dear