Math, asked by sachi79, 9 months ago

Five years hence the age of Jacob will be three times that of his son. Five years ago Jacob's age was seven times that of his son. What are the present ages?

Answer with step by step explanation.Wrong answer will be reported.​

Answers

Answered by jnbasha0209
0

Let 'x' be the present age of jacob and 'y' be the age of his son

As per question

x+5=3(y+5).....(1)

x−5=7(y−5).......(2)

Adding (1) and (2)

2x=3y+15+7y−35

2x=10y−20

x=5y−10...(3)

Putting (3) in (1)

5y−5=3y+15

2y=20

y=10

Putting in (3)

x=5×10−10

x=40

Therefore Present age of Jacob is 40 years and his son is 10 years.

Answered by Anonymous
1

Age of Jacob is 40 and his son is 10

PLEASE REFER THE ATTACHMENT

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