Math, asked by amrit104930, 6 months ago

Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacob's age was seven times that of his son. What are their present ages? ​

Answers

Answered by saniya2080
1

Step-by-step explanation:

Let 'x' be the present age of jacob and 'y' be the age of his son

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per question

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−35

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+15

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)x=5×10−10

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)x=5×10−10x=40

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)x=5×10−10x=40Therefore Present age of Jacob is 40 years and his son is 10 years.

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