Math, asked by shaikhanisa1983, 9 months ago

Five years hence, the age of jacob will be tree times that of his son. Five years ago, Jacob's age was seven times that of his son. what are their present ages?​

Answers

Answered by ronak7165
0

Answer:

Therefore Present age of Jacob is 40 years and his son is 10 years.

Step-by-step explanation:

Let 'x' be the present age of jacob and 'y' be the age of his son

As per question

x+5=3(y+5).....(1)

x−5=7(y−5).......(2)

Adding (1) and (2)

2x=3y+15+7y−35

2x=10y−20

x=5y−10...(3)

Putting (3) in (1)

5y−5=3y+15

2y=20

y=10

Putting in (3)

x=5×10−10

x=40

Therefore Present age of Jacob is 40 years and his son is 10 years.

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Answered by piya1191
2

Answer:

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