five years, hence the age of man will be three times that of his son. 5 years ago, the father age was 7 times the age of his son. what are their present age?
Answers
Solution :
Let the present age of man's be r years.
Let the present age of son's be m years.
A/q
The age of man will be (r+5) years.
The age of son will be (m+5) years.
The age of man will be (r-5) years.
The age of son will be (m-5) years.
∴Putting the value of r in equation (1),we get;
∴Putting the value of m in equation (2),we get;
Thus;
The present age of man's will be r = 40 years.
The present age of son's will be m = 10 years.
☆
5 years ago, the father age was 7 times the age of his son.
five years, hence the age of man will be three times that of his son.
☆
find their present ages
☆
let the son's present age be y
let the father's present age be x
☆
➪ 5 years ago
the father age was 7 times the age of his son.
➦x - 5 = 7 ( y - 5 )
➦ x - 5 = 7y - 35
➦ x - 7y = -35 + 5
➦ x - 7y = - 30
➦ 7y - x = +30 --------( i )
➪ 5 years hence
the age of man will be three times that of his son.
➦ x + 5 = 3 ( y + 5 )
➦ x + 5 = 3y + 15
➦ x - 3y = 15 - 5
➦ x - 3y = 10 ----------( ii )
☆ Solving simultaneously
7y - x = 30
-3y + x = 10
_______________
4y = 40
y = 40 / 4
y = 10
_______________
- putting value of y in eq ( i )
➦7y - x = 30
➦7 x 10 - x = 30
➦70 - x = 30
➦ - x = 30 - 70
➦ - x = - 40
➦ x = 40
__________________________
☆Present age of the son
☆Present age of the father