Question

five years henge the age of anubhab will be three times that of his son five years ago anubhab age was seven times that of his son what are their present ages​

Answer 1

Answer:

Step-by-step explanation:

Let Anubhav's present age be 'x'

And his son's present age be 'y'

5 years hence,

(x+5)=3(y+5) -equation 1

5 years ago,

(x-5)=7(y-5)-equation 2

From equation 1 we get,

x=3y+10

From equation 2 we get,

x= 7y-30

Substitute value of x we get,

3y+10=7y-30

>40=4y

y=40/4

y=10

X=3y+10(equation 1)

X=3(10)+10

X=4

therefore Anubhav's present age is 40 and his son's age is 10

Answer 2

Answer:

Step-by-step explanation:

Let seven years, age of Swati was x years and age of Varun was 5x² years

Present age of Swati = ( x + 7 ) years

Present age of Varun = ( 5x² + 7 ) years

Given, after 3 years swati's age will be 2 / 5 of Varun's age.

Age of Swati after 3 years = ( x + 7 + 3 ) years = ( x + 10 ) years

Age of Varun after 3 years = ( 5x² + 7 + 3 ) years = ( 5x² + 10 ) years

Given, age of Swati after 3 years = age of varun after 3 years

( x + 10 ) = 2 / 5 × ( 5x² + 10 )

( x + 10 ) = 2( x² + 2 )

x + 10 = 2x² + 4

2x² - x + 4 - 10 = 0

2x² - x - 6 = 0

2x² - 4x + 3x - 6 = 0

2x( x - 2 ) + 3( x - 2 ) = 0

x = 2 [ Age can't be negative ]

Therefore,

present age of Swati = ( 2 + 7 ) = 9 years

present age of Varun = 5(2)²+7=27 years

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