Five years , the age of a father was twice the age of his son. The sum of their present ages is 70 years. Find their present ages?
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Five years ago : Let the age of son be x, then age of father = 2x
Now : Son's age = x+5, Father's age = 2x+5
Sum of their ages = 3x+10=70 ⇒ x=20
Present age of son = x+5 = 20+5 =25
Present age of father = 2x+5 = 40+5 = 45
Now : Son's age = x+5, Father's age = 2x+5
Sum of their ages = 3x+10=70 ⇒ x=20
Present age of son = x+5 = 20+5 =25
Present age of father = 2x+5 = 40+5 = 45
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