fixed charge in a taxi is Rs x and charges per km is Rs y . if fare for 10 km is Rs70, then write the given data in form of linear equation in two variables. also represent it graphically. what will be fixed charges , if charges per km are Rs 5?
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6y+4x is equal to 70 and fixed charge is ten
Answered by
1
given,
fixed charge=x
charge per km=y
no. of kms =10
cost=70
=>70=x+10y
if x=10,
=>70=10+10y
=>60=10y
=>y=6
=>(x,y)=(10,6)
if x=20,
=>70=20+10y
=>50=10y
=>y=5
=>(x,y)=(20,5)
if the charges per km is 5 rupees,
according to the question,
no. of km travelled=10km
cost=70
=>70=x+10y
=>70=x+10(5)
=>70=x+50
=>x=20
fixed charge is 20 rupees
HOPE U CAN UNDERSTAND
fixed charge=x
charge per km=y
no. of kms =10
cost=70
=>70=x+10y
if x=10,
=>70=10+10y
=>60=10y
=>y=6
=>(x,y)=(10,6)
if x=20,
=>70=20+10y
=>50=10y
=>y=5
=>(x,y)=(20,5)
if the charges per km is 5 rupees,
according to the question,
no. of km travelled=10km
cost=70
=>70=x+10y
=>70=x+10(5)
=>70=x+50
=>x=20
fixed charge is 20 rupees
HOPE U CAN UNDERSTAND
nikki1231:
pls mark it as brainliest
what
can u give me the graph of it PLZZ
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