Question

FLE 3.
Divide 2x² + 3x +1 by (x + 1).​

Answer 1

Answer:

=2x+1

Step-by-step explanation:

2x^2+3x+1=(2x+1)(x+1)

=(2x+1)(x+1)/(x+1)

=2x+1

Answer 2

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$\large\mathcal\red{solution}$

$p(x) = 2x {}^{2} + 3x + 1 \\ \\ now \: \: applying \: the \: \: remainder \: theorem \\ (x + 1) = 0 \\ x = - 1 \\ \\ now \: \: p( - 1) = 2( - 1) {}^{2} + 3( -1 ) + 1 = 0 \\ therfore \: p(x) \: is \: divisible \: by \: (x + 1) \\ \\ now \: \: \\ = 2x {}^{2} + 3x + 1 \\ = 2x {}^{2} + 2x + x + 1 \\ = 2x(x + 1) + 1(x + 1) \\ = (2x + 1)(x + 1) \\ \\ therefore \\ \frac{2x {}^{2} + 3x + 1 }{(x + 1)} \\ = \frac{ (2x + 1)(x + 1)}{(x + 1)} \\ = 2x + 1$

$\large\mathcal\red{hope\: this \: helps \:you......}$