Question

floor arrangment reasoning question

Answer 1

OK what is the question

Answer 2

There are 8 children – A, B, C, D, E, F, G and H who live on different floors of a 8-floor building numbered 1 to 8 not necessarily in the same order. They have different chocolates – 11, 16, 19, 25, 34, 41, 46 and 50 again not necessarily in the same order.

The one who lives on 6th floor has 25 chocolates. One children lives between F and the one having 25 chocolates. G lives below F on an even numbered floor. G does not have 25 chocolates. The one having 46 chocolates lives just above G. Two children Live between F and H. H lives below F. The total of number of chocolates with D and H is a multiple of 4. Two children live between A and the one having 41 chocolates. A lives above G. The one having 41 chocolates live above A. B has 34 chocolates. The one having 11 chocolates lives just above the one having 16 chocolates. 1 child lives between C and E. The difference between the number of chocolates with E and G is 6

How many children live above E?
A) 1
B) 2
C) 4
D) None
E) 5







Who has 41 chocolates?
A)C
B) E
C) F
D) H
E) B




Who lives on third floor?
A)A
B) B
C) C
D) D
E) E