Question

Floor of a room is of dimensions 5m by 4m and it is covered with circular tiles of dimensions 50 cm each. Find the area of the floor that remains uncovered by tiles.

QUALITY CONTENT NEEDED!!!!!!!

Answer 1

Heya!

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Diameter of 1 tile = 0.5m
Radius = 0.5/2 = 0.25 m

Number of tiles laid along length of room = 5/0.5=10

Number of tiles laid along breadth of room = 4/0.5=8

Total tiles that can be laid = 10+8=18 tiles

Area of 80 tiles = 2πr^2

= 2×22/7×0.25×0.25
= 15.7 m^2

Area of floor= L×B
= 5×4
= 20 m^2

Area of the floor that remains uncovered by tiles = 20-15.7
= 4.3 m^2

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Hope it helps...!!!

Answer 2

Total area 5x4=20m^2
Diameter of circle =. 5m
Let one square tile be of. 5x.5 dimensions
Therefore area of one tile =. 5x.5=.25m^2
Now numbers of such tiles = (total area /area of one tile) = 20/.25= 80
There will be one circle in one tile
Therefore 80 circles in 80 tiles
Area of one circle = (22/7)x(.5^2)/4 =(11/56)m^2
Area left in one tile = area of one tile-area of one circle = 3/56
Now for 80 tiles = 80x3/56 =30/7

Therefore area left uncovered by the circle tiles is 30/7 = 4.285 m^2