Question

floor of a square room of side 10 m is to be completely covered with square tiles, each having length 50c.m. the smallest number of tiles needed is.​

Answer 1

Answer:

4 tiles

Step-by-step explanation:

First find the area of square room

Area of Square = (Side)^2

=(10)^2

=100 m^2

Area of square tile=(50)^2cm

=2500cm^2 or 25m^2

Number of tiles required= 100m^2 / 25m^2

=4 tiles

Answer 2

The smallest number of tiles needed is 400

Solution:

Square room of side 10 m

Find the area of square room

$\text{Area of square} = side^2$

$\text{Area of square} = 10^2 = 10 \times 10\\\\\text{Area of square} = 100\ m^2$

Convert to cm

1 cm = 100 m

Therefore,

$100\ m^2 = 100 \times 100 \times 100\ cm^2$

Square tiles, each having length 50 cm

Find the area of square tiles

$\text{ Area of square tile } = 50^2 = 2500\ cm^2$

Find the number of tiles needed

$\text{Number of tiles } = \frac{ \text{ area of square room }}{ \text{ area of square tiles }}$

$\text{Number of tiles } = \frac{100 \times 100 \times 100}{2500}\\\\\text{Number of tiles } = 400$

Thus the smallest number of tiles needed is 400

Learn more:

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