Question

Floor tiles are 25 cm squares. How many tiles will be needed for a

rectangular lawn 2m long and 10m wide. Find the total cost at the

rate of Rs 8 per tile.​

Answer 1

Step-by-step explanation:

2m = 200 cm, 10 m = 1000 cm

area of lawn= 200×1000 = 200000 cm sq.

tile area = 25 cm sq.

so,

=(200000)/25

=8000 tiles needed

but tile rate 8 /= per tile

hence total cost = 8000×8

=64000 i.e. the answer

Answer 2

$\sf\blue{Given:-}$

$\sf{ Area \: of \: Floor \: tiles = 25 {cm}^{2} }$

$\sf{Cost \: of \: one \: tile = Rs. 8}$

$\sf{ Length \: of \: Rectangular \: lawn = 2m}$

$\sf{ Breadth \: of \: Rectangular \: lawn =10m}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\blue{Formula \: Used:-}$

$\sf{Area \: of \: Rectangular \: lawn = Length × Breadth}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\blue{Solution:-}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{ Area \: of \: Floor \: tiles = 25 {cm}^{2} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{Area \: of \: Rectangular \: lawn = Length × Breadth}$

$\sf{Area \: of \: Rectangular \: lawn = 2m × 10m}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\blue{Convert \: m \: into \: cm}$

$\sf \blue{1m = 100cm}$

$\sf \blue{ 2m= 2 \times 100cm}$

$\sf \blue{ \: \: \: \: \: \: = 200cm}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf \blue{ 10m= 10 \times 100cm}$

$\sf \blue{ \: \: \: \: \: \: \: \: \: = 1000cm}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{Area \: of \: Rectangular \: lawn = 200cm \times 1000cm }$

$\sf{Area \: of \: Rectangular \: lawn = 200000 {cm}^{2} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\blue{No.of tiles = \frac{Area of Rectangular lawn}{Area of tiles}}$

$\sf\blue{No. \: of \: tiles = \frac{ \cancel{200000cm}^{2} }{ \cancel {25cm}^{2} }}$

$\sf\blue{No. \: of \: tiles = 8000}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{Cost \: of \: one \: tile = Rs. 8}$

$\sf{Cost \: of \: 8000\: tile = Rs. 8 \times 8000}$

$\sf \blue{Cost \: of \: 8000 \: tile = Rs.64000}$