flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm how many such tiles are required to cover a floor of area 1080 square
Answers
Answered by
18
Solution:
Given : base= 24 cm
Height= 20 cm
Area of floor= 1080 m²= 1080×100×100cm²
[1m²= 10000cm²]
Area of the Parallelogram = base x height
= 24 x 10 = 240 cm²
Area of 1 tile = 240 cm²
[Tiles are in the shape of a parallelogram]
Number of tiles required= Area of the Floor/Area of the Tiles
= 1080 X100 X100/240 =45000
Number of tiles required to cover a Floor= 45000
========================================================
Hope this will help you...
Pls mark brainliest and thanks
Hope it helps
Thank you
Given : base= 24 cm
Height= 20 cm
Area of floor= 1080 m²= 1080×100×100cm²
[1m²= 10000cm²]
Area of the Parallelogram = base x height
= 24 x 10 = 240 cm²
Area of 1 tile = 240 cm²
[Tiles are in the shape of a parallelogram]
Number of tiles required= Area of the Floor/Area of the Tiles
= 1080 X100 X100/240 =45000
Number of tiles required to cover a Floor= 45000
========================================================
Hope this will help you...
Pls mark brainliest and thanks
Hope it helps
Thank you
Answered by
3
Given: Base of parallelogram is 24 cm
and height is 10cm
To find: Number of tiles when total area is 1080 square centimetre (cm not mentioned in question)
Solution:
Area of parallelogram= base × height
= 24×10= 240 square centimetre
Tiles required =
Total area÷ area of 1 tile= 1080÷240
=4.5 tiles
Hence 4 and a half tiles are required to completely cover floor.
and height is 10cm
To find: Number of tiles when total area is 1080 square centimetre (cm not mentioned in question)
Solution:
Area of parallelogram= base × height
= 24×10= 240 square centimetre
Tiles required =
Total area÷ area of 1 tile= 1080÷240
=4.5 tiles
Hence 4 and a half tiles are required to completely cover floor.
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